Physics question 10 points? - pendulum clock works earth taken moon
A pendulum clock, which is very good on the work of the Earth to the Moon, where g = 1.63 m/s2. When the clock starts at 12:00 clock, what you read on the moon 24.0 hours on Earth?
Sunday, January 31, 2010
Pendulum Clock Works Earth Taken Moon Physics Question 10 Points?
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T = 2π (L / G) ^ 0.5
T ≅ √ (1 / g)
T_moon = T_earth (g_earth / g_moon) ^ 0.5 = (9.8/1.63) ^ 0.5
T_moon = 2.452 T_earth
A pendulum started at 12:00, where on earth is 24:00 clock, while the moon at 12.00 clock + (24 - 12) / 2.452 = 16:54
Length of pendulum = 1 m
Period of a pendulum is given by
T = 2π (L / G) ^ (1 / 2)
Deadline for the full vibration 1 = 2.00607 ~ 2 sec; vibration Number = 43200
To the moon, g = 1.63
And used the formula, comes the time to 3.85 sec
After completion of the clock an hour (3600 / 2) = 1800 vibrations
In 24 hours, ie, 86,400 seconds completed this clock 86400/3.83 = 22441.551
And the time for the oscillation clock = 1800
Number of hours trying to spend about 24 hours on Earth = 22,441.551 / 1800 = 12.46 hours
I would say this about the 1230!
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